Find Nth Catalan Number

C 0 = C 1 = 1 and C n = (2n)! ((n+1)!n!) = i=0 n-1 C i C n-1-i = 2(2n-1) n+1 C n-1 for n > 2

Hint

Observe recursive relationship from definition, C(n) is sum of C(i) times C(n - 1 - i) from i = 0 to i < n, create recurisive function calls. The second form of recursive relationship is drived by C(n) / C(n - 1), simplify its equation, then move C(n - 1) to the right.

# Python implementation
def C(n):
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// Javascript implementation
function C(n) {
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