Find Nth Fibonacci number (Memoization)

Given a positive integer n, find the nth Fibonacci number. Fibonacci numbers, when it starts from 0, are calculaed as F(n), where F(1) = 0, F(2) = 1, and F(n) = F(n-1) + F(n-2) for n > 2. Example of first few Fibonacci numbers are 0, 1, 1, 2, 3, 5, 8, 13, 21, 34.

Hint

This algorithm uses memoization to improve performance. It's same as the recursive version of Fibonacci, but with a special 'cache' to store results. The 'cache key' is crucial. It's how we identify and store past results. Sometimes we need one key, sometimes multiple keys. We add code to:

# Python implementation
cache = {}

def fib(n):
  if n < 2:
    return 0

  if n == 2:
    return 1

  if n not in cache:
    cache[n] = fib(n - 1) + fib(n - 2)

  return cache[n]

n = 5

print(fib(n))
// Javascript implementation
const cache = {}

function fib(n) {
  if (n < 2) {        
    return 0;
  }

  if (n == 2) {        
    return 1;
  }

  if (cache[n] === undefined) {
    cache[n] = fib(n - 1) + fib(n - 2);
  } 
  
  return cache[n];
}

const n = 5;

console.log(fib(n));